In the right triangle shown, AC = AC
and
BC = BC
. What is AB
?
We want to find c
; let a = BC
and b = AC
.
So c^2 = BC^2 + AC^2 = AB2
.
Then, c = \sqrt{AB2}
.
Simplifying the radical gives c = formattedSquareRootOf(AB2).
In the right triangle shown, bside = AC
and
AB = AB
. What is aside
?
We want to find a
; let b = AC
and c = AB
.
So a^2 = c^2 - b^2 = AB^2 - AC^2 = BC2
.
Then, a = \sqrt{BC2}
.
Simplifying the radical gives a = formattedSquareRootOf(BC2).
We know a^2 + b^2 = c^2
.