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  Mgh = Kt + Kr = 1/2 Mv^2 + 1/2 Iw^2
 
  Mgh = Kt + Kr = 1/2 Mv^2 + 1/2 Iw^2
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For a solid sphere, Kt/Kr =5/2 (see[http://cnx.org/content/m14391/latest/ Work and energy in rolling motion])
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For a solid sphere, Kt/Kr =5/2 (see [http://cnx.org/content/m14391/latest/ Work and energy in rolling motion])
       
[[File:Acceleration.jpg]]
 
[[File:Acceleration.jpg]]
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A simpler experiment is to accelerate a ball down a curved ramp, measure the horizontal exit velocity and predict the landing position as shown below.
    
==Links==
 
==Links==
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